"Let x be the amount loaned at 7% annual interest so that 11000-x represents the amount loaned at 9% annual interest.

The total interest earned for both loans was $860.00 so we can write: 0.07x+0.09(11000-x)=860

Solve for x: 0.07x+900-0.09x=860

990-0.02x=860

-0.02x=-130

x=-130/-0.02=6500

Hence, the amount loaned at 7% was $6500 and the amount loaned at 9% was $11000-$6500=$4500"

The total interest earned for both loans was $860.00 so we can write: 0.07x+0.09(11000-x)=860

Solve for x: 0.07x+900-0.09x=860

990-0.02x=860

-0.02x=-130

x=-130/-0.02=6500

Hence, the amount loaned at 7% was $6500 and the amount loaned at 9% was $11000-$6500=$4500"